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A random sample of 10 motorists buying petrol are found to spend an average of £58.30 with estimated standard error £5.25.  Calculate a 95% confidence interval for the expected spending of motorists at this petrol station.

I got 10 of these questions so if someone can help me do this one i think i can do the rest. Thanks in advance.

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  • $\begingroup$ Do you know the formula to calculate a confidence interval, given a mean, standard deviation and sample size? $\endgroup$
    – graydad
    Dec 11, 2014 at 17:10
  • $\begingroup$ Z(a/2) * standard deviation/ square root of sample size I think. $\endgroup$ Dec 11, 2014 at 17:20

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Your interval is defined by $$\left(\overline x-z^*\frac{\sigma}{\sqrt{N}},\space\overline x+z^*\frac{\sigma}{\sqrt{N}}\right)$$ You already know $\overline x = 58.3, \space N=10, \space\sigma = 5.25$. Your $z^*$ value is determined by how wide you want your confidence interval. Since you want a $95\%$ interval and know that $95\%$ of a normally distributed population is contained within $1.96$ standard deviations from the mean, you want $z^* = 1.96$. The rest is just a matter of plugging in numbers. Your sample size is extremely small, so you may also want to make a note of that in your answer.

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  • $\begingroup$ Cheers, This is a lot of help. Thanks mate. $\endgroup$ Dec 11, 2014 at 17:30
  • $\begingroup$ Glad to help; please accept my answer if you have no further questions and don't need any more help :) $\endgroup$
    – graydad
    Dec 11, 2014 at 20:01

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