Consider the following facts:
A Frobenius group is a transitive permutation group on a finite set, such that no non-trivial element fixes more than one point and some non-trivial element fixes a point.
The subgroup $H$ of a Frobenius group $G$ fixing a point of the set $X$ is called the Frobenius complement.
(The following is a theorem due to Frobenius.)
The identity element together with all elements not in any conjugate of H form a normal subgroup called the Frobenius kernel K.
The Frobenius group G is the semidirect product of K and H.
Do we can determine structure Automorphims of a frobenius group?