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What do the square bracket symbols mean? Are they what I hear are "sets"? And when it is in an equation, how is it interpreted?

Here is an example:

$$\dfrac{dy}{dx}[2x2+y(x)2]=50x+2y(dy/dx)=0$$

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It very much depends on the context. Could you show us a specific instance? –  Dylan Moreland Feb 2 '12 at 1:26
    
I found this on sosmath.com/calculus/diff/der05/der05.html: $$dy/dx[2x^2 + y(x)^2] = 50x + 2y(dy/dx) = 0$$ –  David Feb 2 '12 at 1:37
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That helps out quite a bit. I think the $[\;]$ there are just parentheses by another "name"; you can replace them with $(\;)$ without fear. People will sometimes use $[\;]$ or $\{\;\}$ for this purpose in order to avoid a forest of $)))))$s. It doesn't seem so necessary here. –  Dylan Moreland Feb 2 '12 at 1:38
    
The square brackets. Next to dy/dx –  David Feb 2 '12 at 1:39
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David, since you seem to have some programming background: almost all symbols in math are heavily 'overloaded'. In your example, the squared brackets, they are simply are replacement for the are normal brackets (do you know what 'dx/dx' means? Just checking...) But they can for instance denote a closed interval as in $x\in[0,1]$, or something completely different... –  Hauke Strasdat Feb 2 '12 at 1:56
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1 Answer

up vote 1 down vote accepted

Sometimes they are the same as parentheses. Like in $\sum \left[ f(n) - g(n) \right]$ or the expected value $\text{E} \left[ X \right]$. They may have different meanings if they are specially defined.

Or if you meant $\{ \}$ then these are braces and yes they are often used to represent sets.

There is a lot of ambiguity in the proper nomenclature.

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No, I don't mean those {}, I mean these [] –  David Feb 2 '12 at 1:34
    
Show us a context we'll give you an answer. With no context, those could mean anything. –  Patrick Da Silva Feb 2 '12 at 1:35
    
See my edit ^^^ –  David Feb 2 '12 at 1:41
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