# closed form solution for summation of $\log(i)$

Is there a way to find a closed form solution for: (Note that base is $2$)

$\displaystyle\sum_{i=1}^n\log_2(i)$

thanks for any help Can't find a formula for this

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Note that $\log a+\log b = \log (ab)$ – E.O. Feb 1 '12 at 6:07
Could we please change the index of summation here to something besides "$i$"? – deoxygerbe Feb 1 '12 at 6:30
@deoxygerbe What's wrong with $i$? – Chris Taylor Feb 1 '12 at 7:52
@ChrisTaylor: It makes the question title ambiguous and confusing. Is the question about the power series for the logarithm of $i=\sqrt{-1}$? (which is what I thought when I first saw the question title) – deoxygerbe Feb 1 '12 at 7:58

$$\sum_{i=1}^n \log i = \log \left(\prod_{i=1}^n i\right) = \log (n!).$$