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I have a question and I would appreciate if you could give me some clues. For a given $\cos\theta_1,\cos\theta_2,\ldots,\cos\theta_n$, how could I calculate $\cos\left(\theta_1+\theta_2+\cdots+\theta_n\right)$? Are there some general equations or identities available?

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1 Answer 1

You can use the formula $\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ several times to reduce to a polynomial in terms of $\sin(\theta_i)$ and $\cos(\theta_i)$ and finally use the equation $\sin^2(a)+\cos^2(b)=1$ to reduce everything in terms of $\cos(\theta_i)$'s.

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Hello. Thank you. I will verify it. I learnt some equations in my high school, like the one you mentioned. But I did not learnt equations of $cos\left(\theta_{1}+\theta_{2}+\cdots+\theta_{n}\right)$ . So I wonder if it exists. –  user18481 Jan 28 '12 at 5:46
    
Hello, I tried. But it did not seem it is work. I know there is a equation $\cos(a+b+c)$. Maybe we could use a iterative method. I am afraid it would be a long equation. –  user18481 Feb 14 '12 at 3:46

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