# Computing $\lim_{(x,y)\to (0,0)}\frac{x+y}{\sqrt{x^2+y^2}}$

What is the result of $\lim_{(x,y)\to (0,0)}\frac{x+y}{\sqrt{x^2+y^2}}$ . I tried to do couple of algebraic manipulations, but I didn't reach to any conclusion.

Thanks a lot.

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Have you tried writing this in polar coordinates so that you take the limits as $r$ goes to $0$? –  Alex Becker Jan 23 '12 at 7:23
Try to set $y = x$ and $y = -x \$ –  WLOG Jan 23 '12 at 7:26
What stef said, and/or $y=0$. –  Did Jan 23 '12 at 7:31
Generally speaking, the first two comments are fairly good approaches to problems like this. –  AD. Jan 23 '12 at 7:33

If $$x=r\cos\theta$$ $$y=r\sin\theta$$ then we have $$\text{lim}_{r\rightarrow 0}\frac{r\cos\theta+r\sin\theta}{r} =\cos\theta+\sin\theta=\sqrt{2}\sin(\theta+\frac{\pi}{4})$$ which depends on the angle of approach to the origin.

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