I have the following system of differential equations: $ \frac{d}{dt} \left[ \begin{array}{c} A(t)\\ N(t)\\\end{array} \right] = \left[ \begin{array}{c c} -(a+b) & 0\\ a & -(a+b)\\ \end{array} \right] \left[ \begin{array}{c} A(t)\\ N(t)\\\end{array} \right] $
I believe I have correctly obtained the eigenvalue to be $\lambda = -(a+b)$ and associated eigenvector to be $\nu = \left[ \begin{array}{c} 0\\ 1\\\end{array} \right]$.
I am trying to solve the system by the following:
$\left[ \begin{array}{c} A(t)\\ N(t)\\\end{array} \right] = \left[ \begin{array}{c} \nu & \nu\end{array} \right] \left[ \begin{array}{c c} \exp^{\lambda t} & 0\\ 0 & \exp^{\lambda t}\\ \end{array} \right]\left[ \begin{array}{c} A(0)\\ N(0)\\\end{array} \right]$
$\left[ \begin{array}{c} A(t)\\ N(t)\\\end{array} \right] = \left[ \begin{array}{c c} 0 & 0\\ 1 & 1\\ \end{array} \right] \left[ \begin{array}{c c} \exp^{-(a+b)t} & 0\\ 0 & \exp^{-(a+b)t}\\ \end{array} \right]\left[ \begin{array}{c} A(0)\\ N(0)\\\end{array} \right]$
$\left[ \begin{array}{c} A(t)\\ N(t)\\\end{array} \right] = \left[ \begin{array}{c} 0\\ A(0)\exp^{-(a+b)t}+N(0)\exp^{-(a+b)t}\\\end{array} \right]$
Clearly I am doing something wrong. I suspect it has something to do with the fact that there is only one eigenvalue for this system. I was hoping Someone could help me figure this out?
Thanks
Mark