I am stuck with the following problem:
Let $n$ be an integer where $n \geq 3,$ and let $u_1,u_2,.....,u_n$ be n linearly independent elements in a vector space over $\Bbb R$. Set $u_0=0$ and $u_{n+1}=u_1.$ Define $v_i=u_i+u_{i+1}$ and $w_i=u_{i-1}+u_i$ for $i=1,2,3,....,n.$ Then which of the following options are correct?
1. $v_1,v_2,....,v_n$ are linearly independent ,if $n=2010.$
2. $v_1,v_2,....,v_n$ are linearly independent ,if $n=2011.$
3. $w_1,w_2,....,w_n$ are linearly independent ,if $n=2010.$
4. $w_1,w_2,....,w_n$ are linearly independent ,if $n=2011.$
My Attempt: I compute $a_1v_1+a_2v_2+.....+a_nv_n=a_1(u_1+u_2)+a_2(u_2+u_3)+....+a_n(u_n+u_1)=(a_1u_1+...+a_nu_n)+(a_1u_2+...+a_nu_1)=a_1u_2+...+a_nu_1$
[since $u_1,u_2,.....,u_n$ be n linearly independent elements in a vector space over $\Bbb R$ (given),$a_1u_1+...+a_nu_n=0$].Now I do not know which way to progress. Since I am supposed to check $v_1,v_2,....,v_n$ are linearly independent ,my aim is to find the value of $n$ for which $a_1v_1+a_2v_2+.....+a_nv_n=0 \implies a_1=a_2=...=a_n=0$.
Can someone point me in the right direction? Thanks in advance for your time.
EDIT: Now as suggested by @Andreas Caranti
I see that for $n=3, a_1v_1+a_2v_2+a_3v_3=a_1(u_1+u_2)+a_2(u_2+u_3)+a_3(u_3+u_1)=u_1(a_1+a_3)+u_2(a_1+a_2)+u_3(a_2+a_2)=0 \implies a_1=a_2=a_3=0.
$
So ${v_1,v_2,v_3}$ are L.I. So, does it mean option $1$ is true ($n=2010$ being a multiple of $3$)?