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By "discrete-time Markov-modulated Poisson process" I mean a semi-Markov process $\{(X_n,T_n):n=0,1,\ldots\} $ which satisfies $$T_{n+1}-T_n\mid X_n\sim\operatorname{Exp}(\lambda_{X_n}), $$ with $\lambda_j>0$ and $$N(t) = \sum_{n=0}^\infty \mathsf 1_{(0,t]}(T_n) $$ the number of arrivals up to time $t$. Let $\alpha$ be the distribution of $X_0$ and assume that $\{X_n\}$ is irreducible and positive recurrent, so a unique stationary distribution $\pi$ exists. Let $\Lambda(t)=\mathbb E[N(t)]$. It is known that in a nonhomogeneous Poisson process with intensity function $\lambda(t)$ that $\Lambda(t)=\int_0^t \lambda(s)\ \mathsf ds$, but here $\lambda(t)=\lambda_{X_{N(t)}}$ is itself a stochastic process, so it is not clear how to compute $\Lambda(t)$.

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  • $\begingroup$ Can you please clarify $t$ in your definition ?Specifically, did you mean that the waiting time for the $n$-th customer is exponential with parameter depending $X_n$ ? $\endgroup$
    – Fnacool
    May 6, 2016 at 16:01
  • $\begingroup$ Ah, let me fix the notation. $\endgroup$
    – Math1000
    May 6, 2016 at 16:14
  • $\begingroup$ @Fnacool It has been corrected. That is what I meant. $\endgroup$
    – Math1000
    May 6, 2016 at 16:18

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