Q: an urn contains 2 red and 3 black balls. Players 1 and 2 withdraw balls from the urn consecutively without replacement until the second red ball is selected. player 1 draws first, then player 2, and so on. Find the probability that player 1 selects the second red ball
My approach: if i let P_1r be player 1 pick red, P_2b = player 2 pick black so on.
P(P_1r) = 2/5
P(P_1b) = 3/5
P(P_2rlP_1r) = 1/4...
but this does not even go near to the right answer... I'm sure there is easy and efficient way to approach this kind of question but i'm stuck with it. can anyone help? thanks in advance!