2
$\begingroup$

Very often I find this definition of rational numbers in my textbooks:

A rational number is a number determined by the ratio of some integer p to some nonzero natural number q.

But numbers $$\frac{-1}{-2};\frac{-2}{-4};...$$ are surely rational. Why the denominator has to be a natural number?

$\endgroup$
2
  • 7
    $\begingroup$ Normalisation. No deeper reason. $\endgroup$ Aug 5, 2015 at 13:37
  • $\begingroup$ A better definition os of course: A rational number is an equivalence class of pairs $(a,b)\in\mathbb Z\times (\mathbb Z\setminus\{0\})$ under the equivalence relation $(a,b)\sim (a',b')\iff ab'=a'b$. For the equivalence class of $(a,b)$ we introduce the notation $\frac ab$. $\endgroup$ Aug 5, 2015 at 14:43

1 Answer 1

4
$\begingroup$

The keyword here is determined. If you prefer, replace the definition by

A rational number is a number that can be written as $\frac{p}{q}$, with $p$ an integer and $q$ a positive integer

$\frac{-1}{-2}$ can be written as $\frac{1}{2}$, so it's a rational number

$\frac{3\pi}{2\pi}$ can be written as $\frac{3}{2}$ so it's also a rational number

$5$ can be written as $\frac{10}{2}$ so it's also a rational number

But

$\sqrt{2}$ can't be written as a number of the form $\frac{p}{q}$, so it's not a rational number .

$\endgroup$
2
  • $\begingroup$ You may want to replace "non-negative" with "positive", since $q$ is at the denominator. $\endgroup$ Aug 5, 2015 at 15:13
  • $\begingroup$ @VincenzoOliva : ooops ;) $\endgroup$
    – Tryss
    Aug 5, 2015 at 15:18

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .