-Solve the differential equation ,with the given condition: $${\partial z \over \partial x}+(2e^x-y){\partial z \over \partial y}=0.\ \ z=y\ \ \ at \ \ \ \ \ x=0. $$
I solve it as follows:
$${dx \over 1}={dy \over 2e^x-y}$$ then that is integrated into (which I would like for someone to explain how)
$$ye^x-e^{2x}=C$$