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Solve equation: $\sqrt{t +9} - \sqrt{t} = 1$
I moved - √t to the left side of the equation $\sqrt{t +9} = 1 -\sqrt{t}$
I squared both sides $(\sqrt{t+9})^2 = (1)^2 (\sqrt{t})^2$
Then I got $t + 9 = 1+ t$
Can't figure it out after that point.
The answer is $16$
after squaring both sides you get:
$$t+9=1-2\sqrt{t}+t\implies4=\sqrt{t} \implies t=16$$
$$\sqrt{t +9} - \sqrt{t} = 1$$
Multiplying by $\sqrt{t +9} + \sqrt{t}$ you get
$$9=\sqrt{t +9} +\sqrt{t} $$
Now adding
$$\sqrt{t +9} + \sqrt{t} =9$$ $$\sqrt{t +9} - \sqrt{t} = 1$$
you get
$$\sqrt{t+9}=5 \Rightarrow t=25-9 $$
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Solve equation: $\sqrt{t +9} - \sqrt{t} = 1$
I moved - √t to the left side of the equation $\sqrt{t +9} = 1 -\sqrt{t}$
I squared both sides $(\sqrt{t+9})^2 = (1)^2 (\sqrt{t})^2$
Then I got $t + 9 = 1+ t$
Can't figure it out after that point.
The answer is $16$
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after squaring both sides you get:
$$t+9=1-2\sqrt{t}+t\implies4=\sqrt{t} \implies t=16$$
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